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v^2-5v+49=-10v
We move all terms to the left:
v^2-5v+49-(-10v)=0
We get rid of parentheses
v^2-5v+10v+49=0
We add all the numbers together, and all the variables
v^2+5v+49=0
a = 1; b = 5; c = +49;
Δ = b2-4ac
Δ = 52-4·1·49
Δ = -171
Delta is less than zero, so there is no solution for the equation
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